s=5,3s^2

Solution for s=5,3s^2 equation:

s=5.3s^2

We move all terms to the left:

s-(5.3s^2)=0

We get rid of parentheses

-5.3s^2+s=0

a = -5.3; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-5.3)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-5.3}=\frac{-2}{-10.6}
=1/5.3
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-5.3}=\frac{0}{-10.6}
=0
$